Friday, June 3, 2016

Just for fun - a combinatorics problem.

Catherine divides the numbers 1, 2, 3 … 16 into 4 groups, each group has 4 numbers. The sums of all numbers in each group are equal. If she knows one group has two numbers 4 and 13, how many she can select the other two numbers of that group?

from FB/Moncton Math Club's post

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